Deleted wrong answer...

if I replace the Repeat statement with an IF statement it works, but I want to preform a loop to count the spaces in the sentence is the finial goal.

It seems a Bug, does not work if the function has two parameters.

no errors:

$value=-1.2345
repeatwhile(Abs($value)>0) 
  print("value="+$value)
  $value=0
endrepeatwhile 

same error:

$value=1.2345
repeatwhile(Round($value,1)>0) 
  print("value="+$value)
  $value=0
endrepeatwhile 

EDIT: The problem is common to RepeatWhile and RepeatUntil statements.

Thanks PTP, Good to know its not just me. I am sure DJ will have it corrected first chance he gets. Until then I will use a if statement and a loop counter. I am surprised this went so long without being reported.

If that syntax parser bug in repeat didn't exist, the code still wouldn't work. It would loop for ever... for infinite and beyond! as Buzzzz would say from Toy Story.

Use the new Count() function from this release: https://synthiam.com/Community/Questions/10983

$haystack = "These are some words"

# how many words are in the haystack? Count by blank space
$cnt = Count($haystack, " ")

print($cnt + " words")

@DJ Count function how did I miss that! That is a bit shorter than I was doing it.

$WordCount = 1
$LetterCount = 0
$TestLength = Length($HumanSaid)
:WordCountLoop1
if(SubString($HumanSaid,$LetterCount,1) != " ")
  $LetterCount = $LetterCount + 1
  Print($LetterCount)
else
  $LetterCount = $LetterCount + 1
  $WordCount = $WordCount + 1
  Print($WordCount)
endif
if($TestLength > $LetterCount)
  goto(WordCountLoop1)
endif  

Thanks again DJ.

You can do this...

$haystack = "Here are some words for you to parse"

# Get the number of words separated by blank space
$wordCount = count($haystack, " ")

REPEAT ($cnt, 0, $wordCount, 1)

  $word = split($hayStack, " ", $cnt)

  print($word)

ENDREPEAT